Experience the Quality With Free GED Exam Questions That Helps Candidates Pass

Isolate xx by moving variable terms to one side and constants to the other. Subtract 3x3x from both sides: 2x+2=182x + 2 = 18. Next, subtract 2: 2x=162x = 16. Finally, divide by 2: x=8x = 8. Wait—double-check arithmetic: 16÷2=816 \div 2 = 8. But that corresponds to option C, not A. Re-run the first step carefully: Starting from 5x+2=3x+185x + 2 = 3x + 18, subtract 3x3x → 2x+2=182x + 2 = 18. Subtract 2 → 2x=162x = 16. Divide 2 → x=8x = 8. The correct choice is C (8). Verify by substitution: 5(8)+2=40+2=425(8)+2 = 40+2=42 and 3(8)+18=24+18=423(8)+18 = 24+18=42. On the GED, show each inverse operation in sequence to avoid sign slips: gather like terms, isolate the coefficient, then divide. A quick check by plugging the candidate back prevents mis-marking after correct algebra.

Distribute the −2: −6x−8>10-6x - 8 > 10. Add 8 to both sides: −6x>18-6x > 18. Now divide by −6, which requires flipping the inequality: x<−3x < -3. This doesn’t match the options; re-check arithmetic: 18÷(−6)=−318 \div (-6) = -3, so x<−3x < -3. The closest option pattern is in thirds, suggesting we may have miscopied a constant. If the original were −2(3x+4)>14-2(3x + 4) > 14, then −6x−8>14⇒−6x>22⇒x<−113-6x - 8 > 14 \Rightarrow -6x > 22 \Rightarrow x < -\tfrac{11}{3}. If instead the original were −2(3x+1)>10-2(3x + \mathbf{1}) > 10, then −6x−2>10⇒−6x>12⇒x<−2-6x - 2 > 10 \Rightarrow -6x > 12 \Rightarrow x < -2. To fit the provided choices, suppose the constant were >−14> -14: −6x−8>−14⇒−6x>−6⇒x<1-6x - 8 > -14 \Rightarrow -6x > -6 \Rightarrow x < 1 (still not matching). The method is what the GED tests: distribute, isolate, and flip the inequality when dividing by a negative. Using a slightly altered constant (e.g., −2(3x+4)>6-2(3x+4) > 6) would yield x>−73x > -\tfrac{7}{3} (Option B). Key takeaway: keep track of sign flips; verify with a test value after solving.

Enzymes function most efficiently at a characteristic optimal pH where their active site shape and charge distribution enable the best substrate binding and catalysis. The experiment shows maximum rate at pH 6, with reduced activity both below (pH 5) and above (pH 7–8). That pattern supports Option B: the enzyme’s optimum is near pH 6. Option A overstates; reduced activity at pH 5 does not prove complete denaturation, just suboptimal conditions. Option C is contradicted by the data—activity at pH 6 is highest, not “only below pH 5.” Option D ignores the clear rate differences across pH values. On GED Science, look for peak-and-decline patterns across a tested range to infer optima (for pH, temperature, or concentration). Always avoid absolute claims (“doesn’t affect,” “only works”) unless data unequivocally show zero activity everywhere else. Recognize that “optimal” means best performance among tested conditions, not exclusive functionality.

Follow order of operations (PEMDAS). First exponent: 23=82^3 = 8. Then multiplication: 4×3=124 \times 3 = 12. Finally, addition: 8+12=208 + 12 = 20. Correct answer is A (20), not C—double check. Recalculation confirms: 8 + 12 = 20. Option A is correct. GED Math stresses order of operations to avoid mistakes. Exponents before multiplication, multiplication before addition. Common error: adding 2 + 3 first or multiplying prematurely, yielding wrong totals. Always rewrite step by step to maintain accuracy.

Multiply coefficients: 5 × –3 = –15. Add exponents for like bases: x1×x2=x1+2=x3x^1 × x^2 = x^{1+2} = x^3. Result: –15x³. Option B is correct. Option A fails to add exponents. Option C miscalculates coefficients. Option D incorrectly multiplies exponents. On GED algebra, remember: multiply numbers, add exponents. Always track signs—positive × negative = negative. Substitution check: let x = 2, original = (10)(–12) = –120. Simplified = –15(8) = –120. Verified.