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Add: 5+10+15+20=505+10+15+20=50. Divide by 4 = 12.5. Correct answer: B. CLEP math frequently tests averages and descriptive statistics.

CLEP History exams stress Cold War strategies. Containment aimed to stop the spread of communism beyond where it already existed, articulated by George Kennan. Nuclear deterrence was part of defense policy, but containment specifically addressed ideology. Options C and D do not capture the Cold War focus.

CLEP Spanish tests tense knowledge. Future tense of “ir” is “iré” → “I will go tomorrow.” Option B mixes preterite with “mañana.” Option C mixes present with “ayer.” Option D misuses imperfect with future time. Correct tense alignment is crucial for CLEP grammar.

CLEP Literature examines sound devices. Onomatopoeia is when words imitate sounds: “buzz.” Option A is personification. Option C is a metaphor. Option D is hyperbole.

CLEP College Algebra outcomes include analyzing quadratic functions using vertex form and completing the square. For f(x)=x2−6x+8f(x)=x^2-6x+8, complete the square: x2−6x=(x−3)2−9x^2-6x=(x-3)^2-9. Thus f(x)=(x−3)2−9+8=(x−3)2−1f(x)=(x-3)^2-9+8=(x-3)^2-1. A perfect-square term (x−3)2(x-3)^2 is always ≥0\ge 0, so the smallest value occurs when it equals 0, at x=3x=3. Substituting x=3x=3 gives f(3)=−1f(3)=-1. Graphically, the parabola opens upward (leading coefficient >0>0) and its vertex at (3,−1)(3,-1) is the minimum point. Alternative methods—using −b/(2a)-b/(2a) to find the vertex’s x-coordinate—yield the same result: with a=1,b=−6a=1, b=-6, x=−(−6)/(2⋅1)=3x=-(-6)/(2\cdot1)=3, then f(3)=−1f(3)=-1. On CLEP algebra items, recognizing vertex form streamlines questions about extrema, axis of symmetry, and transformations. Also note that choosing options like 11 or −5-5 often reflects arithmetic slips (e.g., miscomputing constant terms after completing the square). Mastery of these standard techniques helps with function analysis, optimization, and interpreting quadratic models across contexts.