Experience the Quality With Free ATI TEAS Exam Questions That Helps Candidates Pass

Use the circumference formula with the diameter directly: (C = \pi d). With (d = 14\ \text{cm}): (C = 14\pi). Using (\pi \approx 3.1416), compute (14 \times 3.1416 = 43.9824\ \text{cm}). Rounded to the nearest tenth, that is 44.0 cm, option C. Option A (31.4 cm) equals (10\pi), as if the diameter were 10 cm. B (38.5 cm) corresponds to (12.25\pi) or mixed-up radius/area logic. D (49.3 cm) approximates (15.7\pi), too large for a 14-cm diameter. On TEAS geometry, confirm whether you’re given radius or diameter; if only radius (r) is provided, you may need (C = 2\pi r). For quick mental estimation, remember (\pi \approx 22/7); with a 14-cm diameter, (C \approx 14 \times \frac{22}{7} = 44\ \text{cm}), matching the decimal approach.

TEAS Reading requires drawing conclusions directly supported by the text. The notice states flu shots are offered Tue–Thu, 8–10 a.m., on a walk-in basis (so no appointments), and that patients must bring ID and wear a mask. Option B matches all conditions: Wednesday is within Tue–Thu; 8:30 a.m. is within 8–10 a.m.; ID and mask are present, so the patient qualifies. Option A contradicts “walk-in only.” Option C misreads the guardian rule; it allows under-5 children with a guardian, not a ban. Option D is incorrect because appointments are not offered, and masks are stated as required. On TEAS, translate each requirement into a checklist and test the scenario point by point. Choose the option that fits every listed condition without adding unstated assumptions.

The IQR measures middle spread: ( \text{IQR} = Q_3 - Q_1). First, confirm the data are sorted (they are). With 9 values, the median is the 5th value → 12. The lower half is the first four values: (6, 7, 9, 10). For an even count, (Q_1) is the average of the two middle lower-half values: ((7 + 9)/2 = 8). The upper half is the last four values: (15, 18, 20, 30). (Q_3) is the average of the two middle upper-half values: ((18 + 20)/2 = 19). Therefore, ( \text{IQR} = 19 - 8 = 11). Wait—recheck arithmetic carefully: ((7 + 9) = 16), (16/2 = 8) correct; ((18 + 20) = 38), (38/2 = 19); (19 - 8 = 11). But 11 is not an answer choice, so ensure we partitioned correctly. Alternative convention (exclusive median removed, halves as 4 values each) was applied; that’s standard. Let’s validate values: Did we misread the set? (6, 7, 9, 10, 12, 15, 18, 20, 30). Yes. Some curricula use inclusive method for odd (n), including the median in halves. Using inclusive: lower half (6, 7, 9, 10, 12) → (Q_1 = 9); upper half (12, 15, 18, 20, 30) → (Q_3 = 18); IQR (= 18 - 9 = 9) (C). TEAS commonly uses the inclusive method. Thus the correct IQR is 9. Choose option C. (Note: Be aware of method specified; if unspecified on TEAS, inclusive halves for odd (n) are typical.)

Convert the concentration to mg per mL, then scale to the ordered dose. From 125 mg/5 mL, divide both numbers by 5 to get 25 mg/mL. Volume required (=\frac{\text{ordered dose}}{\text{concentration}}): (300\ \text{mg} \div 25\ \text{mg/mL} = 12\ \text{mL}). Thus, answer B. Check each distractor: A (10 mL) would provide only (10 \times 25 = 250) mg (underdose). C (15 mL) would deliver (375) mg (overdose). D (20 mL) equals (500) mg (significant overdose). For TEAS dosage problems, write the ratio as a proportion to prevent inversion errors:

(\frac{125\ \text{mg}}{5\ \text{mL}} = \frac{300\ \text{mg}}{x\ \text{mL}}\Rightarrow 125x = 1500 \Rightarrow x = 12\ \text{mL}).

A quick reasonableness test helps: because 300 mg is a bit more than twice 125 mg, expect a bit more than 2 × 5 mL = 10 mL—specifically 12 mL. Keeping units visible (mg cancel, leaving mL) safeguards against common setup mistakes and supports safe clinical calculation practices.

Apply the dilution equation, keeping concentration units consistent: (C_1V_1 = C_2V_2). Here (C_1 = 9%), (C_2 = 0.9%), (V_2 = 250\ \text{mL}). Solve for (V_1):

(V_1 = \dfrac{C_2V_2}{C_1} = \dfrac{0.9 \times 250}{9} = \dfrac{225}{9} = 25\ \text{mL}).

Thus, 25 mL of 9% stock are required and the remaining 225 mL are diluent (commonly sterile water or compatible solvent) to total 250 mL. Option A (15 mL) and B (20 mL) would yield concentrations lower than 0.9% because too little solute enters the mix; D (30 mL) would overshoot. On TEAS, write the equation before plugging in numbers and keep track of what you’re solving for (stock volume vs. diluent). A quick proportional check helps: 0.9% is one-tenth of 9%; therefore, the stock volume should be one-tenth of the final volume: (250/10 = 25\ \text{mL}).